Probability

Here are some essential questions for Class 10 Mathematics Chapter 15, Probability, thoughtfully chosen to aid students in their preparation for the CBSE Class 10 Mathematics Examination in 2023-24. By practicing these varied problems, students can enhance their comprehension of Probability concepts and refine their problem-solving skills.

Table of Content

In Chapter 14 of Class 10 Mathematics, Probability, we will delve into the Classical Definition of Probability. This concept allows us to quantify the likelihood of an event occurring by comparing the number of favorable outcomes to the total possible outcomes. Additionally, we will solve simple problems to determine the probability of specific events.

Probability is a measure that quantifies the likelihood of an event occurring. It is expressed as a value between 0 and 1, where 0 represents an impossible event, and 1 represents a certain event. Probability helps us understand and predict outcomes in various situations.

(b)\(\frac{1}{4}\)

(c)\(\frac{12}{13}\)

(d)\(\frac{3}{4}\)

**Ans. **(c)\(\frac{12}{13}\)

**Explanation:**Total number of possible outcomes = 52

Number of aces in the pack = 4

Thus, the probability of not drawing an ace

∴ P(E) =\(\frac{52-4}{52}\) =\(\frac{12}{13}\)

(b)\(\frac{3}{5}\)

(c)\(\frac{1}{10}\)

(d)None of these

**Ans. **(b)\(\frac{3}{5}\)

**Explanation:**Total number of possible outcomes = 10

The total number of favourable outcomes = 6

∴ P(E) = \(\frac{6}{10}\) = \(\frac{3}{5}\)

**Ans. **probability that the drawn card is neither a king nor a queen

\(=\frac{11}{13}\)

**Explanation:**The number of cards =52

Number of kings and queens=4+4=8

Thus, number of favorable outcomes

= 52−8 = 44

∴ P(E) = \(\frac{44}{52}=\frac{11}{13}\)

**Ans.** The probability of drawing a (i) face card

\(=\frac{3}{13}\)

and (ii) a card which is neither a king nor a red card

\(=\frac{6}{13}\)

**Explanation:**∴ P(E) =\( \frac{12}{52}=\frac{3}{13}\)

(ii) The number of favourable outcomes of drawing neither a king nor a red card

= 52 – (2 + 26)

= 24

∴ P(E)=\( \frac{24}{52}=\frac{6}{13}\)

**Ans. **The number of white balls = 12.

**Explanation: **Let the number of white balls be x.

Thus, the total number of the possible outcomes

= 6 + x

Now, the favourable outcomes if the black ball is drawn = 6

∴ P(B) =\(\frac{6}{6+x}\)

Again, the favourable outcomes if the white ball is drawn = x

∴ P(W) = \(\frac{6}{6+x}\)

According to the question,

\(\frac{6}{6+x}=2\begin{pmatrix} \frac{6}{6+x} \end{pmatrix}\)

⇒ x = 12

Hence, the number of white balls = 12.

To improve your understanding of the Probability chapter, you can explore oswal.io. This platform offers a range of practice questions designed to make learning easier. By practicing these questions, you can strengthen your grasp of probability concepts and enhance your skills in solving probability-related problems.

**Ans: **The probability of an event is calculated by dividing the number of favorable outcomes by the total possible outcomes.

**Ans: **The sum of the probabilities of all possible outcomes in an experiment is equal to 1.

**Ans: **The probability of an event not occurring is calculated by subtracting the probability of the event occurring from 1.

**Ans: **A probability of 0.5 represents an event that is equally likely to occur or not to occur.

**Ans: **An event is a specific outcome or set of outcomes in an experiment or situation.